Eight queens puzzle: Difference between revisions

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{{Short description|Mathematical problem set on a chessboard}}
The '''eight queens puzzle''' is the problem of putting eight [[chess]] queens on an 8x8 chessboard such that none of them is able to attack any other using the standard chess queen's moves.
{{Use dmy dates|date=January 2020}}
(Piece colour is ignored, and any piece is assumed to be able to attack any other.)
{{Chess diagram
That is to say, no two pieces should share the same row, column, or diagonal.
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|The only symmetrical solution to the eight queens puzzle ([[up to]] rotation and reflection)
}}


The '''eight queens puzzle''' is the problem of placing eight [[chess]] [[Queen (chess)|queen]]s on an 8×8 [[chessboard]] so that no two queens threaten each other; thus, a solution requires that no two queens share the same row, column, or diagonal. There are 92 solutions. The problem was first posed in the mid-19th century. In the modern era, it is often used as an example problem for various [[computer programming]] techniques.
The eight queens problem has 92 distinct solutions, or 12 distinct solutions if symmetry operations are taken into consideration.


The eight queens puzzle is a special case of the more general '''''n'' queens problem''' of placing ''n'' non-attacking queens on an ''n''×''n'' chessboard. Solutions exist for all [[natural number]]s ''n'' with the exception of ''n'' = 2 and ''n'' = 3. Although the exact number of solutions is only known for ''n'' ≤ 27, the [[asymptotic analysis|asymptotic growth rate]] of the number of solutions is approximately (0.143 ''n'')<sup>''n''</sup>.
<h3>The eight queens puzzle as an example problem for algorithm design</h3>


==History==
The eight queens puzzle is a good example of a simple but non-trivial problem that can be solved by a [[recursion|recursive]] [[algorithm]], by phrasing the ''n''-queen problem inductively in terms of adding a single queen to any solution to the (''n''-1)-queen problem.
[[Chess composer]] [[Max Bezzel]] published the eight queens puzzle in 1848. [[Franz Nauck]] published the first solutions in 1850.<ref name="rouse_ball_1960">[[W. W. Rouse Ball]] (1960) "The Eight Queens Problem", in ''Mathematical Recreations and Essays'', Macmillan, New York, pp. 165–171.</ref> Nauck also extended the puzzle to the ''n'' queens problem, with ''n'' queens on a chessboard of ''n''×''n'' squares.
The [[induction]] bottoms out with the solution to the 0-queen problem, which is an empty chessboard.


Since then, many [[mathematician]]s, including [[Carl Friedrich Gauss]], have worked on both the eight queens puzzle and its generalized ''n''-queens version. In 1874, [[Siegmund Günther|S. Günther]] proposed a method using [[determinant]]s to find solutions.<ref name="rouse_ball_1960"/> [[James Whitbread Lee Glaisher|J.W.L. Glaisher]] refined Gunther's approach.
This technique is much more efficient than the naive brute-force algorithm, which considers all 64<sup>8</sup> possible blind placements of eight queens, and then filters these to remove all placements that place two queens either on the same square or in mutually attacking positions.
This very poor algorithm will, amongst other things, produce the same results over and over again in all the different permutations of the assignments of the eight queens, as well as repeating the same computations over and over again for the different sub-sets of each solution.


In 1972, [[Edsger Dijkstra]] used this problem to illustrate the power of what he called [[structured programming]]. He published a highly detailed description of a [[Depth-first search|depth-first]] [[Backtracking|backtracking algorithm]].<ref>[[Ole-Johan Dahl|O.-J. Dahl]], [[E. W. Dijkstra]], [[C. A. R. Hoare]] ''Structured Programming'', Academic Press, London, 1972 {{ISBN|0-12-200550-3}}, pp.&nbsp;72–82.</ref>
It is often used as an example problem for non-traditional appraches, such as [[constraint programming]], [[logic programming]] or [[genetic algorithms]].


== Constructing and counting solutions when ''n'' = 8 ==
The problem of finding all solutions to the 8-queens problem can be quite computationally expensive, as there are 4,426,165,368 possible arrangements of eight queens on an 8×8 board,{{efn|The number of [[combination]]s of 8 squares from 64 is the [[binomial coefficient]] <sub>64</sub>C<sub>8</sub>.}} but only 92 solutions. It is possible to use shortcuts that reduce computational requirements or rules of thumb that avoids [[Brute-force search|brute-force computational techniques]]. For example, by applying a simple rule that chooses one queen from each column, it is possible to reduce the number of possibilities to 16,777,216 (that is, 8<sup>8</sup>) possible combinations. Generating [[permutation]]s further reduces the possibilities to just 40,320 (that is, [[factorial|8!]]), which can then be checked for diagonal attacks.


The eight queens puzzle has 92 distinct solutions. If solutions that differ only by the [[symmetry]] operations of rotation and reflection of the board are counted as one, the puzzle has 12 solutions. These are called ''fundamental'' solutions; representatives of each are shown below.
<h3>Example program in Python</h3>


A fundamental solution usually has eight variants (including its original form) obtained by rotating 90, 180, or 270° and then reflecting each of the four rotational variants in a mirror in a fixed position. However, one of the 12 fundamental solutions (solution 12 below) is identical to its own 180° rotation, so has only four variants (itself and its reflection, its 90° rotation and the reflection of that).{{efn|Other symmetries are possible for other values of ''n''. For example, there is a placement of five nonattacking queens on a 5×5 board that is identical to its own 90° rotation. Such solutions have only two variants (itself and its reflection). If ''n'' > 1, it is not possible for a solution to be equal to its own reflection because that would require two queens to be facing each other.}} Thus, the total number of distinct solutions is 11×8 + 1×4 = 92.
''This is very quickly hacked together - is it correct?''
''Can anyone do better than this, in an elegant language?''


All fundamental solutions are presented below:
# This uses the insights that
# - no two pieces can share the same row
# - any solution for n queens on a nxm board must contain a solution
# for n-1 queens on a (n-1)xm board
# - proceeding in this way will always keep the queens in order, and generate
# each solution only once
def safe_queen(new_row, new_col, sol):
# check against each piece on each of the n-1 existing rows
for row in range(new_row):
if (sol[row] == new_col or
(sol[row] + row) == (new_col + new_row) or
(sol[row] - row) == (new_col - new_row)):
return 0
return 1


{{col-begin}}
# This tries to add a queen on all columns of row new_row
{{col-break}}
def add_queen(new_row, width, previous_solutions):
{{Chess diagram small
solutions = []
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for sol in previous_solutions:
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# try to place a queen on each col on row n-1
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for new_col in range(width):
|__|__|__|__|__|__|ql|__
# print 'trying', new_col, 'on row', new_row, 'in width', width
|__|__|ql|__|__|__|__|__
if safe_queen(new_row, new_col, sol):
|__|__|__|__|__|__|__|ql
# If no interference, add this solution to the list
|__|ql|__|__|__|__|__|__
solutions = solutions + [ sol + [new_col] ]
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return solutions
|ql|__|__|__|__|__|__|__
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|Solution 1
}}
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|Solution 2
}}
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|Solution 3
}}
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|Solution 4
}}
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|Solution 5
}}
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|Solution 6
}}
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|Solution 7
}}
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|Solution 8
}}
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|Solution 9
}}
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|Solution 10
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|Solution 11
}}
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|Solution 12
}}


{{col-end}}
# This solves the n-queens problem on a board with n rows and width columns

# - the result is a list of solutions
Solution 10 has the additional property that [[No-three-in-line problem|no three queens are in a straight line]].
# - solutions are expressed as a list of column positions for queens, indexed by row

# - rows and columns are indexed from zero
==Existence of solutions==
def n_queens(n, width):

if n <= 0:
Brute-force algorithms to count the number of solutions are computationally manageable for {{math|1=''n''&nbsp;=&nbsp;8}}, but would be intractable for problems of {{math|1=''n''&nbsp;≥&nbsp;20}}, as 20! = 2.433 × 10<sup>18</sup>. If the goal is to find a single solution, one can show solutions exist for all ''n'' ≥ 4 with no search whatsoever.<ref name=bernhardsson>{{cite journal |author=Bo Bernhardsson |date=1991 |title=Explicit Solutions to the N-Queens Problem for All N |journal=SIGART Bull. |volume=2 |issue=2 |pages=7 |doi=10.1145/122319.122322|s2cid=10644706 }}</ref><ref>E. J. Hoffman et al., "Construction for the Solutions of the m Queens Problem". ''Mathematics Magazine'', Vol. XX (1969), pp.&nbsp;66–72. [http://penguin.ewu.edu/~trolfe/QueenLasVegas/Hoffman.pdf] {{Webarchive|url=https://web.archive.org/web/20161108102345/http://penguin.ewu.edu/~trolfe/QueenLasVegas/Hoffman.pdf |date=8 November 2016 }}</ref>
return [[]] # one solution, the empty list
These solutions exhibit stair-stepped patterns, as in the following examples for ''n'' = 8, 9 and 10:
{{col-begin-fixed}}
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| Staircase solution for 8 queens
}}
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| Staircase solution for 9 queens
}}
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| Staircase solution for 10 queens
}}
{{col-end}}

The examples above can be obtained with the following formulas.<ref name=bernhardsson /> Let (''i'', ''j'') be the square in column ''i'' and row ''j'' on the ''n'' × ''n'' chessboard, ''k'' an integer.

One approach<ref name=bernhardsson /> is

# If the remainder from dividing ''n'' by 6 is not 2 or 3 then the list is simply all even numbers followed by all odd numbers not greater than ''n''.
# Otherwise, write separate lists of even and odd numbers (2, 4, 6, 8 – 1, 3, 5, 7).
# If the remainder is 2, swap 1 and 3 in odd list and move 5 to the end ('''3, 1''', 7, '''5''').
# If the remainder is 3, move 2 to the end of even list and 1,3 to the end of odd list (4, 6, 8, '''2''' – 5, 7, 9, '''1, 3''').
# Append odd list to the even list and place queens in the rows given by these numbers, from left to right (a2, b4, c6, d8, e3, f1, g7, h5).

For {{math|1=''n''&nbsp;=&nbsp;8}} this results in fundamental solution 1 above. A few more examples follow.

* 14 queens (remainder 2): 2, 4, 6, 8, 10, 12, 14, 3, 1, 7, 9, 11, 13, 5.
* 15 queens (remainder 3): 4, 6, 8, 10, 12, 14, 2, 5, 7, 9, 11, 13, 15, 1, 3.
* 20 queens (remainder 2): 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 3, 1, 7, 9, 11, 13, 15, 17, 19, 5.

==Counting solutions for other sizes ''n'' ==
===Exact enumeration===
There is no known formula for the exact number of solutions for placing ''n'' queens on an {{math|''n'' × ''n''}} board i.e. the number of [[independent set (graph theory)|independent set]]s of size ''n'' in an {{math|''n'' × ''n''}} [[queen's graph]]. The 27×27 board is the highest-order board that has been completely enumerated.<ref>[http://github.com/preusser/q27 The Q27 Project]</ref> The following tables give the number of solutions to the ''n'' queens problem, both fundamental {{OEIS|id=A002562}} and all {{OEIS|id=A000170}}, for all known cases.

{| class="wikitable" style="text-align:right;"
!style="padding: 0em .5em;"|''n''
|fundamental
|all
|-
!style="padding: 0em .5em;"|1
|1
|1
|-
!style="padding: 0em .5em;"|2
|0
|0
|-
!style="padding: 0em .5em;"|3
|0
|0
|-
!style="padding: 0em .5em;"|4
|1
|2
|-
!style="padding: 0em .5em;"|5
|2
|10
|-
!style="padding: 0em .5em;"|6
|1
|4
|-
!style="padding: 0em .5em;"|7
|6
|40
|-
!style="padding: 0em .5em;"|8
|12
|92
|-
!style="padding: 0em .5em;"|9
|46
|352
|-
!style="padding: 0em .5em;"|10
|92
|724
|-
!style="padding: 0em .5em;"|11
|341
|2,680
|-
!style="padding: 0em .5em;"|12
|1,787
|14,200
|-
!style="padding: 0em .5em;"|13
|9,233
|73,712
|-
!style="padding: 0em .5em;"|14
|45,752
|365,596
|-
!style="padding: 0em .5em;"|15
|285,053
|2,279,184
|-
!style="padding: 0em .5em;"|16
|1,846,955
|14,772,512
|-
!style="padding: 0em .5em;"|17
|11,977,939
|95,815,104
|-
!style="padding: 0em .5em;"|18
|83,263,591
|666,090,624
|-
!style="padding: 0em .5em;"|19
|621,012,754
|4,968,057,848
|-
!style="padding: 0em .5em;"|20
|4,878,666,808
|39,029,188,884
|-
!style="padding: 0em .5em;"|21
|39,333,324,973
|314,666,222,712
|-
!style="padding: 0em .5em;"|22
|336,376,244,042
|2,691,008,701,644
|-
!style="padding: 0em .5em;"|23
|3,029,242,658,210
|24,233,937,684,440
|-
!style="padding: 0em .5em;"|24
|28,439,272,956,934
|227,514,171,973,736
|-
!style="padding: 0em .5em;"|25
|275,986,683,743,434
|2,207,893,435,808,352
|-
!style="padding: 0em .5em;"|26
|2,789,712,466,510,289
|22,317,699,616,364,044
|-
!style="padding: 0em .5em;"|27
|29,363,495,934,315,694
|234,907,967,154,122,528
|}
The number of placements in which furthermore no three queens line on any straight line is known for <math>n \leq 23</math> {{OEIS|id=A365437}}.

=== Asymptotic enumeration ===
In 2021, Michael Simkin proved that for large numbers ''n'', the number of solutions of the ''n'' queens problem is approximately <math>(0.143n)^n</math>.<ref>{{Cite web|last=Sloman|first=Leila|date=2021-09-21|title=Mathematician Answers Chess Problem About Attacking Queens|url=https://www.quantamagazine.org/mathematician-answers-chess-problem-about-attacking-queens-20210921/|access-date=2021-09-22|website=Quanta Magazine|language=en}}</ref> More precisely, the number <math>\mathcal{Q}(n)</math> of solutions has [[asymptotic growth]]
<math display="block">
\mathcal{Q}(n) = ((1 \pm o(1))ne^{-\alpha})^n
</math>
where <math>\alpha</math> is a constant that lies between 1.939 and 1.945.<ref>{{Cite arXiv|last=Simkin|first=Michael|author-link=Michael Simkin|date=2021-07-28|title=The number of $n$-queens configurations|class=math.CO|eprint=2107.13460v2|language=en}}</ref> (Here ''o''(1) represents [[little o notation]].)

If one instead considers a [[flat torus|toroidal]] chessboard (where diagonals "wrap around" from the top edge to the bottom and from the left edge to the right), it is only possible to place ''n'' queens on an <math>n \times n</math> board if <math>n \equiv 1,5 \mod 6.</math> In this case, the asymptotic number of solutions is<ref>{{Cite arXiv|last=Luria|first=Zur|date=2017-05-15|title=New bounds on the number of n-queens configurations|class=math.CO|eprint=1705.05225v2|language=en}}</ref><ref>{{Cite arXiv|last1=Bowtell|first1=Candida|last2=Keevash|first2=Peter|authorlink2 = Peter Keevash|date=2021-09-16|title=The $n$-queens problem|class=math.CO|eprint=2109.08083v1|language=en}}</ref>
<math display="block">T(n) = ((1+o(1))ne^{-3})^n.</math>

==Related problems==
;Higher dimensions
:Find the number of non-attacking queens that can be placed in a ''d''-dimensional chess {{boardgloss|gamespace|space}} of size ''n''. More than ''n'' queens can be placed in some higher dimensions (the smallest example is four non-attacking queens in a 3×3×3 chess space), and it is in fact known that for any ''k'', there are higher dimensions where ''n''<sup>''k''</sup> queens do not suffice to attack all spaces.<ref>J. Barr and S. Rao (2006), The n-Queens Problem in Higher Dimensions, Elemente der Mathematik, vol 61 (4), pp. 133–137.</ref><ref>{{cite web | url= http://queens.lyndenlea.info/beyond2d.php | title= Queens On A Chessboard – Beyond The 2nd Dimension | access-date=2020-01-27 | author= Martin S. Pearson | format= php | language= en}}</ref>
;Using pieces other than queens
:On an 8×8 board one can place 32 [[knight (chess)|knight]]s, or 14 [[bishop (chess)|bishop]]s, 16 [[king (chess)|king]]s or eight [[rook (chess)|rook]]s, so that no two pieces attack each other. In the case of knights, an easy solution is to place one on each square of a given color, since they move only to the opposite color. The solution is also easy for rooks and kings. Sixteen kings can be placed on the board by dividing it into 2-by-2 squares and placing the kings at equivalent points on each square. Placements of ''n'' rooks on an ''n''×''n'' board are in direct correspondence with order-''n'' [[permutation matrices]].
;Chess variations
:Related problems can be asked for [[chess variations]] such as [[shogi]]. For instance, the ''n''+''k'' dragon kings problem asks to place ''k'' [[Shogi#equipment|shogi pawns]] and ''n''+''k'' mutually nonattacking [[Shogi#equipment|dragon kings]] on an ''n''×''n'' shogi board.<ref>{{Cite journal|last=Chatham|first=Doug|date=1 December 2018|title=Reflections on the n +k dragon kings problem|journal=Recreational Mathematics Magazine|language=en|volume=5|issue=10|pages=39–55|doi=10.2478/rmm-2018-0007|doi-access=free}}</ref>
;Nonstandard boards
:[[George Pólya|Pólya]] studied the ''n'' queens problem on a [[torus|toroidal]] ("donut-shaped") board and showed that there is a solution on an ''n''×''n'' board if and only if ''n'' is not divisible by 2 or 3.<ref>G. Pólya, Uber die "doppelt-periodischen" Losungen des n-Damen-Problems, George Pólya: Collected papers Vol. IV, G-C. Rota, ed., MIT Press, Cambridge, London, 1984, pp.&nbsp;237–247
</ref>
;Domination
:Given an ''n''×''n'' board, the '''domination number''' is the minimum number of queens (or other pieces) needed to attack or occupy every square. For ''n'' = 8 the queen's domination number is 5.<ref>{{citation|last1=Burger|first1=A. P.|last2=Cockayne|first2=E. J.|last3=Mynhardt|first3=C. M.|author3-link=Kieka Mynhardt|doi=10.1016/0012-365X(95)00327-S|issue=1–3|journal=Discrete Mathematics|mr=1428557|pages=47–66|title=Domination and irredundance in the queens' graph|volume=163|year=1997|hdl=1828/2670|hdl-access=free}}</ref><ref>{{citation|last=Weakley|first=William D.|editor1-last=Gera|editor1-first=Ralucca|editor1-link=Ralucca Gera|editor2-last=Haynes|editor2-first=Teresa W.|editor2-link=Teresa W. Haynes|editor3-last=Hedetniemi|editor3-first=Stephen T.|contribution=Queens around the world in twenty-five years|doi=10.1007/978-3-319-97686-0_5|location=Cham|mr=3889146|pages=43–54|publisher=Springer|series=Problem Books in Mathematics|title=Graph Theory: Favorite Conjectures and Open Problems – 2|year=2018}}</ref>
;Queens and other pieces
:Variants include mixing queens with other pieces; for example, placing ''m'' queens and ''m'' knights on an ''n''×''n'' board so that no piece attacks another<ref>{{Cite web |url=http://www.vector.org.uk/archive/v213/hui213.htm |title=Queens and knights problem |access-date=20 September 2005 |archive-url=https://web.archive.org/web/20051016004909/http://www.vector.org.uk/archive/v213/hui213.htm |archive-date=16 October 2005 |url-status=dead }}</ref> or placing queens and pawns so that no two queens attack each other.<ref>{{cite journal|last1=Bell |first1=Jordan |last2=Stevens |first2=Brett
|title=A survey of known results and research areas for '''n'''-queens
|journal=Discrete Mathematics|volume=309 |number=1|year=2009|pages=1–31|doi=10.1016/j.disc.2007.12.043|doi-access=free}}</ref>
;[[Magic square]]s
:In 1992, Demirörs, Rafraf, and Tanik published a method for converting some magic squares into ''n''-queens solutions, and vice versa.<ref>O. Demirörs, N. Rafraf, and M.M. Tanik. Obtaining n-queens solutions from magic squares and constructing magic squares from n-queens solutions. Journal of Recreational Mathematics, 24:272–280, 1992</ref>
;[[Latin square]]s
:In an ''n''×''n'' matrix, place each digit 1 through ''n'' in ''n'' locations in the matrix so that no two instances of the same digit are in the same row or column.
;[[Exact cover]]
:Consider a matrix with one primary column for each of the ''n'' ranks of the board, one primary column for each of the ''n'' files, and one secondary column for each of the 4''n'' − 6 nontrivial diagonals of the board. The matrix has ''n''<sup>2</sup> rows: one for each possible queen placement, and each row has a 1 in the columns corresponding to that square's rank, file, and diagonals and a 0 in all the other columns. Then the ''n'' queens problem is equivalent to choosing a subset of the rows of this matrix such that every primary column has a 1 in precisely one of the chosen rows and every secondary column has a 1 in at most one of the chosen rows; this is an example of a generalized [[exact cover]] problem, of which [[sudoku]] is another example.
; ''n''-queens completion
:The completion problem asks whether, given an ''n''×''n'' chessboard on which some queens are already placed, it is possible to place a queen in every remaining row so that no two queens attack each other. This and related questions are [[NP-complete]] and [[Sharp-P-complete|#P-complete]].<ref>{{cite journal
| last1 = Gent
| first1 = Ian P.
| last2 = Jefferson
| first2 = Christopher
| last3 = Nightingale
| first3 = Peter
| title = Complexity of ''n''-Queens Completion
| journal = [[Journal of Artificial Intelligence Research]]
| volume = 59
| pages = 815–848
| date = August 2017
| language = en
| url = https://jair.org/index.php/jair/article/view/11079/26262
| issn = 1076-9757
| doi = 10.1613/jair.5512
| access-date = 7 September 2017| doi-access = free
| hdl = 10023/11627
| hdl-access = free
}}</ref> Any placement of at most ''n''/60 queens can be completed, while there are partial configurations of roughly ''n''/4 queens that cannot be completed.<ref>{{cite journal |last1=Glock |first1=Stefan |last2=Correia |first2=David Munhá |last3=Sudakov |first3=Benny |title=The ''n''-queens completion problem |journal=Research in the Mathematical Sciences |date=6 July 2022 |volume=9 |issue=41 |page=41 |doi=10.1007/s40687-022-00335-1 |pmid=35815227 |pmc=9259550 |s2cid=244478527 |doi-access=free }}</ref>

==Exercise in algorithm design==
Finding all solutions to the eight queens puzzle is a good example of a simple but nontrivial problem. For this reason, it is often used as an example problem for various programming techniques, including nontraditional approaches such as [[constraint programming]], [[logic programming]] or [[genetic algorithm]]s. Most often, it is used as an example of a problem that can be solved with a [[recursion|recursive]] [[algorithm]], by phrasing the ''n'' queens problem inductively in terms of adding a single queen to any solution to the problem of placing ''n''&minus;1 queens on an ''n''×''n'' chessboard. The [[mathematical induction|induction]] bottoms out with the solution to the 'problem' of placing 0 queens on the chessboard, which is the empty chessboard.

This technique can be used in a way that is much more efficient than the naïve [[brute-force search]] algorithm, which considers all 64<sup>8</sup>&nbsp;=&nbsp;2<sup>48</sup>&nbsp;= 281,474,976,710,656 possible blind placements of eight queens, and then filters these to remove all placements that place two queens either on the same square (leaving only 64!/56!&nbsp;= 178,462,987,637,760 possible placements) or in mutually attacking positions. This very poor algorithm will, among other things, produce the same results over and over again in all the different [[permutation]]s of the assignments of the eight queens, as well as repeating the same computations over and over again for the different sub-sets of each solution. A better brute-force algorithm places a single queen on each row, leading to only 8<sup>8</sup>&nbsp;=&nbsp;2<sup>24</sup>&nbsp;= 16,777,216 blind placements.

It is possible to do much better than this.
One algorithm solves the eight [[Rook (chess)|rooks]] puzzle by generating the permutations of the numbers 1 through 8 (of which there are 8! = 40,320), and uses the elements of each permutation as indices to place a queen on each row.
Then it rejects those boards with diagonal attacking positions.

[[Image:Eight-queens-animation.gif|thumb|This animation illustrates [[backtracking]] to solve the problem. A queen is placed in a column that is known not to cause conflict. If a column is not found the program returns to the last good state and then tries a different column.]]
The [[backtracking]] [[depth-first search]] program, a slight improvement on the permutation method, constructs the [[search tree]] by considering one row of the board at a time, eliminating most nonsolution board positions at a very early stage in their construction.
Because it rejects rook and diagonal attacks even on incomplete boards, it examines only 15,720 possible queen placements.
A further improvement, which examines only 5,508 possible queen
placements, is to combine the permutation based method with the early
pruning method: the permutations are generated depth-first, and
the search space is pruned if the [[partial permutation]] produces a
diagonal attack.
[[Constraint programming]] can also be very effective on this problem.

[[File:8queensminconflict.gif|thumbnail|right|[[Min-conflicts algorithm|min-conflicts]] solution to 8 queens]]
An alternative to exhaustive search is an 'iterative repair' algorithm, which typically starts with all queens on the board, for example with one queen per column.<ref>[http://citeseerx.ist.psu.edu/viewdoc/download;jsessionid=4DC9292839FE7B1AFABA1EDB8183242C?doi=10.1.1.57.4685&rep=rep1&type=pdf A Polynomial Time Algorithm for the N-Queen Problem] by Rok Sosic and Jun Gu, 1990. Describes run time for up to 500,000 Queens which was the max they could run due to memory constraints.</ref> It then counts the number of conflicts (attacks), and uses a heuristic to determine how to improve the placement of the queens. The '[[Min-conflicts algorithm|minimum-conflicts]]' [[heuristic]] – moving the piece with the largest number of conflicts to the square in the same column where the number of conflicts is smallest – is particularly effective: it easily finds a solution to even the 1,000,000 queens problem.<ref>{{Cite journal |last1=Minton |first1=Steven |last2=Johnston |first2=Mark D. |last3=Philips |first3=Andrew B. |last4=Laird |first4=Philip |date=1992-12-01 |title=Minimizing conflicts: a heuristic repair method for constraint satisfaction and scheduling problems |url=https://dx.doi.org/10.1016/0004-3702%2892%2990007-K |journal=Artificial Intelligence |language=en |volume=58 |issue=1 |pages=161–205 |doi=10.1016/0004-3702(92)90007-K |s2cid=14830518 |issn=0004-3702|hdl=2060/19930006097 |hdl-access=free }}</ref><ref>{{Cite journal |last1=Sosic |first1=R. |last2=Gu |first2=Jun |date=October 1994 |title=Efficient local search with conflict minimization: a case study of the n-queens problem |url=https://ieeexplore.ieee.org/document/317698 |journal=IEEE Transactions on Knowledge and Data Engineering |volume=6 |issue=5 |pages=661–668 |doi=10.1109/69.317698 |issn=1558-2191}}</ref>

Unlike the backtracking search outlined above, iterative repair does not guarantee a solution: like all [[greedy algorithm|greedy]] procedures, it may get stuck on a local optimum. (In such a case, the algorithm may be restarted with a different initial configuration.) On the other hand, it can solve problem sizes that are several orders of magnitude beyond the scope of a depth-first search.

As an alternative to backtracking, solutions can be counted by recursively enumerating valid partial solutions, one row at a time. Rather than constructing entire board positions, blocked diagonals and columns are tracked with bitwise operations. This does not allow the recovery of individual solutions.<ref>{{cite journal|last1=Qiu|first1=Zongyan|title=Bit-vector encoding of n-queen problem|journal=ACM SIGPLAN Notices|date=February 2002|volume=37|issue=2|pages=68–70|doi=10.1145/568600.568613}}</ref><ref>{{cite tech report|first=Martin|last=Richards|title=Backtracking Algorithms in MCPL using Bit Patterns and Recursion|institution=University of Cambridge Computer Laboratory|number=UCAM-CL-TR-433|date=1997|url=http://www.cl.cam.ac.uk/~mr10/backtrk.pdf}}</ref>

==Sample program==
The following program is a translation of [[Niklaus Wirth]]'s solution into the [[Python (programming language)|Python]] programming language, but does without the [[Array data type|index arithmetic]] found in the original and instead uses [[List (abstract data type)|lists]] to keep the program code as simple as possible. By using a [[coroutine]] in the form of a [[Generator (computer programming)|generator function]], both versions of the original can be unified to compute either one or all of the solutions. Only 15,720 possible queen placements are examined.<ref>{{cite journal|last=Wirth |first=Niklaus |author-link=Niklaus Wirth |title=Algorithms + Data Structures = Programs |journal=Prentice-Hall Series in Automatic Computation |publisher=Prentice-Hall |year=1976 |isbn=978-0-13-022418-7 |title-link=Algorithms + Data Structures = Programs |bibcode=1976adsp.book.....W}} p. 145</ref><ref>{{cite book |last=Wirth |first=Niklaus |date=2012 |orig-date=orig. 2004 |title=Algorithms and Data Structures |version=Oberon version with corrections and authorized modifications |url=https://people.inf.ethz.ch/wirth/AD.pdf |chapter=The Eight Queens Problem |pages=114–118}}</ref>
<syntaxhighlight lang="python">
def queens(n: int, i: int, a: list, b: list, c: list):
if i < n:
for j in range(n):
if j not in a and i + j not in b and i - j not in c:
yield from queens(n, i + 1, a + [j], b + [i + j], c + [i - j])
else:
else:
yield a
return add_queen(n-1, width, n_queens(n-1, width))


for solution in queens(8, 0, [], [], []):
print(solution)
</syntaxhighlight>

==In popular culture==
*In the game ''[[The 7th Guest]]'', the 8th Puzzle: "The Queen's Dilemma" in the game room of the Stauf mansion is the [[de facto]] eight queens puzzle.<ref>{{cite book|url=http://www.thealmightyguru.com/Wiki/images/a/a7/7th_Guest%2C_The_-_Official_Strategy_Guide%2C_The.pdf |title=The 7th Guest: The Official Strategy Guide|first=Rusel|last=DeMaria|publisher=Prima Games|isbn=978-1-5595-8468-5|date=Nov 15, 1993|access-date=Apr 22, 2021}}</ref>{{rp|pages=48–49,289–290}}
*In the game [[Professor Layton and the Curious Village]], the 130th puzzle: "Too Many Queens 5" ({{lang|ja|クイーンの問題5}}) is an eight queens puzzle.<ref>{{cite web|url=https://layton-fushigi.g-takumi.com/nazo130.html |title=ナゾ130 クイーンの問題5|work=ゲームの匠|language=ja|access-date=September 17, 2021}}</ref>


==See also==
for sol in n_queens(8, 8):
* [[Mathematical game]]
print sol
* [[Mathematical puzzle]]
* [[No-three-in-line problem]]
* [[Rook polynomial]]
* [[Costas array]]


==Notes==
{{notelist}}


==References==
See also:
{{Reflist}}
* [[chess problem]]
* [[functional programming]]
* [[mathematical game]]


==Further reading==
External links to solutions using:
* {{cite journal|last1=Bell |first1=Jordan |last2=Stevens |first2=Brett
* [http://www.atarimagazines.com/v3n12/Queens8.html Atari BASIC]
|title=A survey of known results and research areas for '''n'''-queens
* [http://www.liacs.nl/~gusz/Flying_Circus/2.Slides/2.Examples/1.8Queens/ Genetic algorithms]
|journal=Discrete Mathematics|volume=309 |number=1|year=2009|pages=1–31|doi=10.1016/j.disc.2007.12.043|doi-access=free}}
* [http://www.scdi.org/%7eavernet/projects/jaskell/queens/ Haskell/Java hybrid]
* {{cite book|last1=Watkins|first1=John J.|year=2004|title=Across the Board: The Mathematics of Chess Problems|location=Princeton|publisher=Princeton University Press|isbn=978-0-691-11503-0|url-access=registration|url=https://archive.org/details/acrossboardma00watk}}
* [http://www.math.utah.edu/%7Ealfeld/queens/queens.html Java]
* [http://www.dcs.ed.ac.uk/home/mlj/demos/queens/ Standard ML]
* {{cite web|url=http://www.csse.monash.edu.au/~lloyd/tildeAlgDS/Recn/Queens3D/
|title=Three Dimensional NxN-Queens Problems|first1=L. |last1= Allison |first2=C.N. |last2= Yee
|first3= M. |last3=McGaughey |year=1988|location=Department of Computer Science, Monash University, Australia}}
* {{cite journal|first1=S. |last1= Nudelman |title=The Modular N-Queens Problem in Higher Dimensions
|journal=Discrete Mathematics|volume=146 |number=1–3|year=1995|pages=159–167|doi=10.1016/0012-365X(94)00161-5|doi-access=free}}
* {{cite journal|first1=M. |last1= Engelhardt |title=Der Stammbaum der Lösungen des Damenproblems (in German, means The pedigree chart of solutions to the 8-queens problem| journal=Spektrum der Wissenschaft |date=August 2010 |pages=68–71 |url=http://www.spektrum.de/artikel/1037434&_z=798888}}
* [http://www.liacs.nl/~kosters/nqueens/papers/gomez2004.pdf ''On The Modular N-Queen Problem in Higher Dimensions''], Ricardo Gomez, Juan Jose Montellano and Ricardo Strausz (2004), Instituto de Matematicas, Area de la Investigacion Cientifica, Circuito Exterior, Ciudad Universitaria, Mexico.
* {{cite book|last=Budd|first=Timothy|date=2002|title=An Introduction to Object-Oriented Programming|edition=3rd|publisher=Addison Wesley Longman|url=https://web.engr.oregonstate.edu/~budd/Books/oopintro3e/info/ReadMe.html|chapter=A Case Study: The Eight Queens Puzzle|chapter-url=https://web.engr.oregonstate.edu/~budd/Books/oopintro3e/info/chap06.pdf|pages=125–145|isbn=0-201-76031-2}}
* {{cite book|last=Wirth|first=Niklaus|date=2004|orig-date=updated 2012|title=Algorithms and Data Structures|version=Oberon version with corrections and authorized modifications|url=https://people.inf.ethz.ch/wirth/AD.pdf|chapter=The Eight Queens Problem|pages=114–118}}


==External links==
{{wikibooks|Algorithm Implementation|Miscellaneous/N-Queens|N-queens problem}}
* {{Mathworld|title=Queens Problem|id=QueensProblem}}
* {{GitHub|sblendorio/queens-cpm}} Eight Queens Puzzle in Turbo Pascal for CP/M
* {{GitHub|gitpel/python-for-fun/blob/master/eight-queens.py}} Eight Queens Puzzle one line solution in Python
* [http://rosettacode.org/wiki/N-queens_problem Solutions in more than 100 different programming languages] (on [[Rosetta Code]])


{{Magic polygons}}
Other external links:
* http://bridges.canterbury.ac.nz/features/eight.html


{{DEFAULTSORT:Eight Queens Puzzle}}
[[talk:Eight_queens_puzzle|/Talk]]
[[Category:Mathematical chess problems]]
[[Category:Enumerative combinatorics]]
[[Category:1848 in chess]]
[[Category:Mathematical problems]]

Latest revision as of 18:01, 4 April 2024

abcdefgh
8
f8 white queen
d7 white queen
g6 white queen
a5 white queen
h4 white queen
b3 white queen
e2 white queen
c1 white queen
8
77
66
55
44
33
22
11
abcdefgh
The only symmetrical solution to the eight queens puzzle (up to rotation and reflection)

The eight queens puzzle is the problem of placing eight chess queens on an 8×8 chessboard so that no two queens threaten each other; thus, a solution requires that no two queens share the same row, column, or diagonal. There are 92 solutions. The problem was first posed in the mid-19th century. In the modern era, it is often used as an example problem for various computer programming techniques.

The eight queens puzzle is a special case of the more general n queens problem of placing n non-attacking queens on an n×n chessboard. Solutions exist for all natural numbers n with the exception of n = 2 and n = 3. Although the exact number of solutions is only known for n ≤ 27, the asymptotic growth rate of the number of solutions is approximately (0.143 n)n.

History[edit]

Chess composer Max Bezzel published the eight queens puzzle in 1848. Franz Nauck published the first solutions in 1850.[1] Nauck also extended the puzzle to the n queens problem, with n queens on a chessboard of n×n squares.

Since then, many mathematicians, including Carl Friedrich Gauss, have worked on both the eight queens puzzle and its generalized n-queens version. In 1874, S. Günther proposed a method using determinants to find solutions.[1] J.W.L. Glaisher refined Gunther's approach.

In 1972, Edsger Dijkstra used this problem to illustrate the power of what he called structured programming. He published a highly detailed description of a depth-first backtracking algorithm.[2]

Constructing and counting solutions when n = 8[edit]

The problem of finding all solutions to the 8-queens problem can be quite computationally expensive, as there are 4,426,165,368 possible arrangements of eight queens on an 8×8 board,[a] but only 92 solutions. It is possible to use shortcuts that reduce computational requirements or rules of thumb that avoids brute-force computational techniques. For example, by applying a simple rule that chooses one queen from each column, it is possible to reduce the number of possibilities to 16,777,216 (that is, 88) possible combinations. Generating permutations further reduces the possibilities to just 40,320 (that is, 8!), which can then be checked for diagonal attacks.

The eight queens puzzle has 92 distinct solutions. If solutions that differ only by the symmetry operations of rotation and reflection of the board are counted as one, the puzzle has 12 solutions. These are called fundamental solutions; representatives of each are shown below.

A fundamental solution usually has eight variants (including its original form) obtained by rotating 90, 180, or 270° and then reflecting each of the four rotational variants in a mirror in a fixed position. However, one of the 12 fundamental solutions (solution 12 below) is identical to its own 180° rotation, so has only four variants (itself and its reflection, its 90° rotation and the reflection of that).[b] Thus, the total number of distinct solutions is 11×8 + 1×4 = 92.

All fundamental solutions are presented below:

Solution 10 has the additional property that no three queens are in a straight line.

Existence of solutions[edit]

Brute-force algorithms to count the number of solutions are computationally manageable for n = 8, but would be intractable for problems of n ≥ 20, as 20! = 2.433 × 1018. If the goal is to find a single solution, one can show solutions exist for all n ≥ 4 with no search whatsoever.[3][4] These solutions exhibit stair-stepped patterns, as in the following examples for n = 8, 9 and 10:

The examples above can be obtained with the following formulas.[3] Let (i, j) be the square in column i and row j on the n × n chessboard, k an integer.

One approach[3] is

  1. If the remainder from dividing n by 6 is not 2 or 3 then the list is simply all even numbers followed by all odd numbers not greater than n.
  2. Otherwise, write separate lists of even and odd numbers (2, 4, 6, 8 – 1, 3, 5, 7).
  3. If the remainder is 2, swap 1 and 3 in odd list and move 5 to the end (3, 1, 7, 5).
  4. If the remainder is 3, move 2 to the end of even list and 1,3 to the end of odd list (4, 6, 8, 2 – 5, 7, 9, 1, 3).
  5. Append odd list to the even list and place queens in the rows given by these numbers, from left to right (a2, b4, c6, d8, e3, f1, g7, h5).

For n = 8 this results in fundamental solution 1 above. A few more examples follow.

  • 14 queens (remainder 2): 2, 4, 6, 8, 10, 12, 14, 3, 1, 7, 9, 11, 13, 5.
  • 15 queens (remainder 3): 4, 6, 8, 10, 12, 14, 2, 5, 7, 9, 11, 13, 15, 1, 3.
  • 20 queens (remainder 2): 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 3, 1, 7, 9, 11, 13, 15, 17, 19, 5.

Counting solutions for other sizes n[edit]

Exact enumeration[edit]

There is no known formula for the exact number of solutions for placing n queens on an n × n board i.e. the number of independent sets of size n in an n × n queen's graph. The 27×27 board is the highest-order board that has been completely enumerated.[5] The following tables give the number of solutions to the n queens problem, both fundamental (sequence A002562 in the OEIS) and all (sequence A000170 in the OEIS), for all known cases.

n fundamental all
1 1 1
2 0 0
3 0 0
4 1 2
5 2 10
6 1 4
7 6 40
8 12 92
9 46 352
10 92 724
11 341 2,680
12 1,787 14,200
13 9,233 73,712
14 45,752 365,596
15 285,053 2,279,184
16 1,846,955 14,772,512
17 11,977,939 95,815,104
18 83,263,591 666,090,624
19 621,012,754 4,968,057,848
20 4,878,666,808 39,029,188,884
21 39,333,324,973 314,666,222,712
22 336,376,244,042 2,691,008,701,644
23 3,029,242,658,210 24,233,937,684,440
24 28,439,272,956,934 227,514,171,973,736
25 275,986,683,743,434 2,207,893,435,808,352
26 2,789,712,466,510,289 22,317,699,616,364,044
27 29,363,495,934,315,694 234,907,967,154,122,528

The number of placements in which furthermore no three queens line on any straight line is known for (sequence A365437 in the OEIS).

Asymptotic enumeration[edit]

In 2021, Michael Simkin proved that for large numbers n, the number of solutions of the n queens problem is approximately .[6] More precisely, the number of solutions has asymptotic growth

where is a constant that lies between 1.939 and 1.945.[7] (Here o(1) represents little o notation.)

If one instead considers a toroidal chessboard (where diagonals "wrap around" from the top edge to the bottom and from the left edge to the right), it is only possible to place n queens on an board if In this case, the asymptotic number of solutions is[8][9]

Related problems[edit]

Higher dimensions
Find the number of non-attacking queens that can be placed in a d-dimensional chess space of size n. More than n queens can be placed in some higher dimensions (the smallest example is four non-attacking queens in a 3×3×3 chess space), and it is in fact known that for any k, there are higher dimensions where nk queens do not suffice to attack all spaces.[10][11]
Using pieces other than queens
On an 8×8 board one can place 32 knights, or 14 bishops, 16 kings or eight rooks, so that no two pieces attack each other. In the case of knights, an easy solution is to place one on each square of a given color, since they move only to the opposite color. The solution is also easy for rooks and kings. Sixteen kings can be placed on the board by dividing it into 2-by-2 squares and placing the kings at equivalent points on each square. Placements of n rooks on an n×n board are in direct correspondence with order-n permutation matrices.
Chess variations
Related problems can be asked for chess variations such as shogi. For instance, the n+k dragon kings problem asks to place k shogi pawns and n+k mutually nonattacking dragon kings on an n×n shogi board.[12]
Nonstandard boards
Pólya studied the n queens problem on a toroidal ("donut-shaped") board and showed that there is a solution on an n×n board if and only if n is not divisible by 2 or 3.[13]
Domination
Given an n×n board, the domination number is the minimum number of queens (or other pieces) needed to attack or occupy every square. For n = 8 the queen's domination number is 5.[14][15]
Queens and other pieces
Variants include mixing queens with other pieces; for example, placing m queens and m knights on an n×n board so that no piece attacks another[16] or placing queens and pawns so that no two queens attack each other.[17]
Magic squares
In 1992, Demirörs, Rafraf, and Tanik published a method for converting some magic squares into n-queens solutions, and vice versa.[18]
Latin squares
In an n×n matrix, place each digit 1 through n in n locations in the matrix so that no two instances of the same digit are in the same row or column.
Exact cover
Consider a matrix with one primary column for each of the n ranks of the board, one primary column for each of the n files, and one secondary column for each of the 4n − 6 nontrivial diagonals of the board. The matrix has n2 rows: one for each possible queen placement, and each row has a 1 in the columns corresponding to that square's rank, file, and diagonals and a 0 in all the other columns. Then the n queens problem is equivalent to choosing a subset of the rows of this matrix such that every primary column has a 1 in precisely one of the chosen rows and every secondary column has a 1 in at most one of the chosen rows; this is an example of a generalized exact cover problem, of which sudoku is another example.
n-queens completion
The completion problem asks whether, given an n×n chessboard on which some queens are already placed, it is possible to place a queen in every remaining row so that no two queens attack each other. This and related questions are NP-complete and #P-complete.[19] Any placement of at most n/60 queens can be completed, while there are partial configurations of roughly n/4 queens that cannot be completed.[20]

Exercise in algorithm design[edit]

Finding all solutions to the eight queens puzzle is a good example of a simple but nontrivial problem. For this reason, it is often used as an example problem for various programming techniques, including nontraditional approaches such as constraint programming, logic programming or genetic algorithms. Most often, it is used as an example of a problem that can be solved with a recursive algorithm, by phrasing the n queens problem inductively in terms of adding a single queen to any solution to the problem of placing n−1 queens on an n×n chessboard. The induction bottoms out with the solution to the 'problem' of placing 0 queens on the chessboard, which is the empty chessboard.

This technique can be used in a way that is much more efficient than the naïve brute-force search algorithm, which considers all 648 = 248 = 281,474,976,710,656 possible blind placements of eight queens, and then filters these to remove all placements that place two queens either on the same square (leaving only 64!/56! = 178,462,987,637,760 possible placements) or in mutually attacking positions. This very poor algorithm will, among other things, produce the same results over and over again in all the different permutations of the assignments of the eight queens, as well as repeating the same computations over and over again for the different sub-sets of each solution. A better brute-force algorithm places a single queen on each row, leading to only 88 = 224 = 16,777,216 blind placements.

It is possible to do much better than this. One algorithm solves the eight rooks puzzle by generating the permutations of the numbers 1 through 8 (of which there are 8! = 40,320), and uses the elements of each permutation as indices to place a queen on each row. Then it rejects those boards with diagonal attacking positions.

This animation illustrates backtracking to solve the problem. A queen is placed in a column that is known not to cause conflict. If a column is not found the program returns to the last good state and then tries a different column.

The backtracking depth-first search program, a slight improvement on the permutation method, constructs the search tree by considering one row of the board at a time, eliminating most nonsolution board positions at a very early stage in their construction. Because it rejects rook and diagonal attacks even on incomplete boards, it examines only 15,720 possible queen placements. A further improvement, which examines only 5,508 possible queen placements, is to combine the permutation based method with the early pruning method: the permutations are generated depth-first, and the search space is pruned if the partial permutation produces a diagonal attack. Constraint programming can also be very effective on this problem.

min-conflicts solution to 8 queens

An alternative to exhaustive search is an 'iterative repair' algorithm, which typically starts with all queens on the board, for example with one queen per column.[21] It then counts the number of conflicts (attacks), and uses a heuristic to determine how to improve the placement of the queens. The 'minimum-conflicts' heuristic – moving the piece with the largest number of conflicts to the square in the same column where the number of conflicts is smallest – is particularly effective: it easily finds a solution to even the 1,000,000 queens problem.[22][23]

Unlike the backtracking search outlined above, iterative repair does not guarantee a solution: like all greedy procedures, it may get stuck on a local optimum. (In such a case, the algorithm may be restarted with a different initial configuration.) On the other hand, it can solve problem sizes that are several orders of magnitude beyond the scope of a depth-first search.

As an alternative to backtracking, solutions can be counted by recursively enumerating valid partial solutions, one row at a time. Rather than constructing entire board positions, blocked diagonals and columns are tracked with bitwise operations. This does not allow the recovery of individual solutions.[24][25]

Sample program[edit]

The following program is a translation of Niklaus Wirth's solution into the Python programming language, but does without the index arithmetic found in the original and instead uses lists to keep the program code as simple as possible. By using a coroutine in the form of a generator function, both versions of the original can be unified to compute either one or all of the solutions. Only 15,720 possible queen placements are examined.[26][27]

def queens(n: int, i: int, a: list, b: list, c: list):
    if i < n:
        for j in range(n):
            if j not in a and i + j not in b and i - j not in c:
                yield from queens(n, i + 1, a + [j], b + [i + j], c + [i - j])
    else:
        yield a


for solution in queens(8, 0, [], [], []):
    print(solution)

In popular culture[edit]

See also[edit]

Notes[edit]

  1. ^ The number of combinations of 8 squares from 64 is the binomial coefficient 64C8.
  2. ^ Other symmetries are possible for other values of n. For example, there is a placement of five nonattacking queens on a 5×5 board that is identical to its own 90° rotation. Such solutions have only two variants (itself and its reflection). If n > 1, it is not possible for a solution to be equal to its own reflection because that would require two queens to be facing each other.

References[edit]

  1. ^ a b W. W. Rouse Ball (1960) "The Eight Queens Problem", in Mathematical Recreations and Essays, Macmillan, New York, pp. 165–171.
  2. ^ O.-J. Dahl, E. W. Dijkstra, C. A. R. Hoare Structured Programming, Academic Press, London, 1972 ISBN 0-12-200550-3, pp. 72–82.
  3. ^ a b c Bo Bernhardsson (1991). "Explicit Solutions to the N-Queens Problem for All N". SIGART Bull. 2 (2): 7. doi:10.1145/122319.122322. S2CID 10644706.
  4. ^ E. J. Hoffman et al., "Construction for the Solutions of the m Queens Problem". Mathematics Magazine, Vol. XX (1969), pp. 66–72. [1] Archived 8 November 2016 at the Wayback Machine
  5. ^ The Q27 Project
  6. ^ Sloman, Leila (21 September 2021). "Mathematician Answers Chess Problem About Attacking Queens". Quanta Magazine. Retrieved 22 September 2021.
  7. ^ Simkin, Michael (28 July 2021). "The number of $n$-queens configurations". arXiv:2107.13460v2 [math.CO].
  8. ^ Luria, Zur (15 May 2017). "New bounds on the number of n-queens configurations". arXiv:1705.05225v2 [math.CO].
  9. ^ Bowtell, Candida; Keevash, Peter (16 September 2021). "The $n$-queens problem". arXiv:2109.08083v1 [math.CO].
  10. ^ J. Barr and S. Rao (2006), The n-Queens Problem in Higher Dimensions, Elemente der Mathematik, vol 61 (4), pp. 133–137.
  11. ^ Martin S. Pearson. "Queens On A Chessboard – Beyond The 2nd Dimension" (php). Retrieved 27 January 2020.
  12. ^ Chatham, Doug (1 December 2018). "Reflections on the n +k dragon kings problem". Recreational Mathematics Magazine. 5 (10): 39–55. doi:10.2478/rmm-2018-0007.
  13. ^ G. Pólya, Uber die "doppelt-periodischen" Losungen des n-Damen-Problems, George Pólya: Collected papers Vol. IV, G-C. Rota, ed., MIT Press, Cambridge, London, 1984, pp. 237–247
  14. ^ Burger, A. P.; Cockayne, E. J.; Mynhardt, C. M. (1997), "Domination and irredundance in the queens' graph", Discrete Mathematics, 163 (1–3): 47–66, doi:10.1016/0012-365X(95)00327-S, hdl:1828/2670, MR 1428557
  15. ^ Weakley, William D. (2018), "Queens around the world in twenty-five years", in Gera, Ralucca; Haynes, Teresa W.; Hedetniemi, Stephen T. (eds.), Graph Theory: Favorite Conjectures and Open Problems – 2, Problem Books in Mathematics, Cham: Springer, pp. 43–54, doi:10.1007/978-3-319-97686-0_5, MR 3889146
  16. ^ "Queens and knights problem". Archived from the original on 16 October 2005. Retrieved 20 September 2005.
  17. ^ Bell, Jordan; Stevens, Brett (2009). "A survey of known results and research areas for n-queens". Discrete Mathematics. 309 (1): 1–31. doi:10.1016/j.disc.2007.12.043.
  18. ^ O. Demirörs, N. Rafraf, and M.M. Tanik. Obtaining n-queens solutions from magic squares and constructing magic squares from n-queens solutions. Journal of Recreational Mathematics, 24:272–280, 1992
  19. ^ Gent, Ian P.; Jefferson, Christopher; Nightingale, Peter (August 2017). "Complexity of n-Queens Completion". Journal of Artificial Intelligence Research. 59: 815–848. doi:10.1613/jair.5512. hdl:10023/11627. ISSN 1076-9757. Retrieved 7 September 2017.
  20. ^ Glock, Stefan; Correia, David Munhá; Sudakov, Benny (6 July 2022). "The n-queens completion problem". Research in the Mathematical Sciences. 9 (41): 41. doi:10.1007/s40687-022-00335-1. PMC 9259550. PMID 35815227. S2CID 244478527.
  21. ^ A Polynomial Time Algorithm for the N-Queen Problem by Rok Sosic and Jun Gu, 1990. Describes run time for up to 500,000 Queens which was the max they could run due to memory constraints.
  22. ^ Minton, Steven; Johnston, Mark D.; Philips, Andrew B.; Laird, Philip (1 December 1992). "Minimizing conflicts: a heuristic repair method for constraint satisfaction and scheduling problems". Artificial Intelligence. 58 (1): 161–205. doi:10.1016/0004-3702(92)90007-K. hdl:2060/19930006097. ISSN 0004-3702. S2CID 14830518.
  23. ^ Sosic, R.; Gu, Jun (October 1994). "Efficient local search with conflict minimization: a case study of the n-queens problem". IEEE Transactions on Knowledge and Data Engineering. 6 (5): 661–668. doi:10.1109/69.317698. ISSN 1558-2191.
  24. ^ Qiu, Zongyan (February 2002). "Bit-vector encoding of n-queen problem". ACM SIGPLAN Notices. 37 (2): 68–70. doi:10.1145/568600.568613.
  25. ^ Richards, Martin (1997). Backtracking Algorithms in MCPL using Bit Patterns and Recursion (PDF) (Technical report). University of Cambridge Computer Laboratory. UCAM-CL-TR-433.
  26. ^ Wirth, Niklaus (1976). "Algorithms + Data Structures = Programs". Prentice-Hall Series in Automatic Computation. Prentice-Hall. Bibcode:1976adsp.book.....W. ISBN 978-0-13-022418-7. p. 145
  27. ^ Wirth, Niklaus (2012) [orig. 2004]. "The Eight Queens Problem". Algorithms and Data Structures (PDF). Oberon version with corrections and authorized modifications. pp. 114–118.
  28. ^ DeMaria, Rusel (15 November 1993). The 7th Guest: The Official Strategy Guide (PDF). Prima Games. ISBN 978-1-5595-8468-5. Retrieved 22 April 2021.
  29. ^ "ナゾ130 クイーンの問題5". ゲームの匠 (in Japanese). Retrieved 17 September 2021.

Further reading[edit]

External links[edit]